java中CyclicBarrier的使用

2年前 (2022) 程序员胖胖胖虎阿
201 0 0

文章目录

  • ​​CyclicBarrier的方法​​
  • ​​CyclicBarrier的使用​​

java中CyclicBarrier的使用

CyclicBarrier是java 5中引入的线程安全的组件。它有一个barrier的概念,主要用来等待所有的线程都执行完毕,然后再去执行特定的操作。

假如我们有很多个线程,每个线程都计算出了一些数据,然后我们需要等待所有的线程都执行完毕,再把各个线程计算出来的数据加起来,的到最终的结果,那么我们就可以使用CyclicBarrier。

CyclicBarrier的方法

我们先看下CyclicBarrier的构造函数:

public CyclicBarrier(int parties, Runnable barrierAction) {if (parties <= 0) throw new IllegalArgumentException();this.parties = parties;this.count = parties;this.barrierCommand = barrierAction;}public CyclicBarrier(int parties) {this(parties, null);}

CyclicBarrier有两个构造函数,第一个只接受一个参数,表示需要统一行动的线程个数。第二个参数叫做barrierAction,表示出发barrier是需要执行的方法。

其中barrierAction是一个Runnable,我们可以在其中定义最后需要执行的工作。

再看下重要await方法:

public int await() throws InterruptedException, BrokenBarrierException {try {return dowait(false, 0L);} catch (TimeoutException toe) {throw new Error(toe); // cannot happen}}public int await(long timeout, TimeUnit unit)throws InterruptedException,   BrokenBarrierException,   TimeoutException {return dowait(true, unit.toNanos(timeout));}

await也有两个方法,一个是带时间参数的,一个是不带时间参数的。

await本质上调用了lock.newCondition().await()方法。

因为有多个parties,下面我们考虑两种情况。

  1. 该线程不是最后一个调用await的线程

在这种情况下,该线程将会进入等待状态,直到下面的情况发送:

  • 最后一个线程调用await()
  • 其他线程中断了当前线程
  • 其他线程中断了其他正在等待的线程
  • 其他线程在等待barrier的时候超时
  • 其他线程在该barrier上调用的reset()方法

如果该线程在调用await()的时候已经设置了interrupted的状态,或者在等待的时候被interrupted,那么将会抛出InterruptedException异常,并清除中断状态。(这里和Thread的interrupt()方法保持一致)

如果任何线程正在等待状态中,这时候barrier被重置。或者在线程调用await方法或者正在等待中,barrier被broken,那么将会抛出BrokenBarrierException。

如果任何线程在等待的时候被中断,那么所有其他等待的线程将会抛出BrokenBarrierException,barrier将会被置为broken状态。

  1. 如果该线程是最后一个调用await方法的

在这种情况,如果barrierAction不为空,那么该线程将会在其他线程继续执行前调用这个barrierAction。

如果该操作抛出异常,那么barrier的状态将会被置为broken状态。

再看看这个reset() 方法:

public void reset() {final ReentrantLock lock = this.lock;lock.lock();try {breakBarrier();   // break the current generationnextGeneration(); // start a new generation} finally {lock.unlock();}}

该方法将会将barrier置为broken状态,并且开启一个新的generation,来进行下一轮的操作。

CyclicBarrier的使用

我们在子线程中生成一个随机的整数队列,当所有的线程都生成完毕之后,我们再将生成的整数全都加起来。看下怎么实现。

定义生成整数队列的子线程:

public class CyclicBarrierUsage implements Runnable {private CyclicBarrier cyclicBarrier;private List<List<Integer>> partialResults;private Random random = new Random();public CyclicBarrierUsage(CyclicBarrier cyclicBarrier,List<List<Integer>> partialResults){this.cyclicBarrier=cyclicBarrier;this.partialResults=partialResults;}@Overridepublic void run() {String thisThreadName = Thread.currentThread().getName();List<Integer> partialResult = new ArrayList<>();// Crunch some numbers and store the partial resultfor (int i = 0; i < 10; i++) {Integer num = random.nextInt(10);System.out.println(thisThreadName+ ": Crunching some numbers! Final result - " + num);partialResult.add(num);}partialResults.add(partialResult);try {System.out.println(thisThreadName+ " waiting for others to reach barrier.");cyclicBarrier.await();} catch (InterruptedException e) {// ...} catch (BrokenBarrierException e) {// ...}}}

上面的子线程接收外部传入的cyclicBarrier和保存数据的partialResults,并在运行完毕调用cyclicBarrier.await()来等待其他线程执行完毕。

看下CyclicBarrier的构建:

CyclicBarrier cyclicBarrier=new CyclicBarrier(5,()->{String thisThreadName = Thread.currentThread().getName();System.out.println(thisThreadName + ": Computing sum of 5 workers, having 10 results each.");int sum = 0;for (List<Integer> threadResult : partialResults) {System.out.print("Adding ");for (Integer partialResult : threadResult) {System.out.print(partialResult+" ");sum += partialResult;}System.out.println();}System.out.println(thisThreadName + ": Final result = " + sum);});

在CyclicBarrier中,我们定义了一个BarrierAction来做最后数据的汇总处理。

运行:

for (int i = 0; i < 5; i++) {Thread worker = new Thread(new CyclicBarrierUsage(cyclicBarrier,partialResults));worker.setName("Thread " + i);worker.start();}

输出结果如下:

Spawning 5 worker threads to compute 10 partial results each
Thread 0: Crunching some numbers! Final result - 5
Thread 0: Crunching some numbers! Final result - 3
Thread 1: Crunching some numbers! Final result - 1
Thread 0: Crunching some numbers! Final result - 7
Thread 1: Crunching some numbers! Final result - 8
Thread 0: Crunching some numbers! Final result - 4
Thread 0: Crunching some numbers! Final result - 6
Thread 0: Crunching some numbers! Final result - 9
Thread 1: Crunching some numbers! Final result - 3
Thread 2: Crunching some numbers! Final result - 1
Thread 0: Crunching some numbers! Final result - 0
Thread 2: Crunching some numbers! Final result - 9
Thread 1: Crunching some numbers! Final result - 3
Thread 2: Crunching some numbers! Final result - 7
Thread 0: Crunching some numbers! Final result - 2
Thread 2: Crunching some numbers! Final result - 6
Thread 1: Crunching some numbers! Final result - 6
Thread 2: Crunching some numbers! Final result - 5
Thread 0: Crunching some numbers! Final result - 0
Thread 2: Crunching some numbers! Final result - 1
Thread 1: Crunching some numbers! Final result - 5
Thread 2: Crunching some numbers! Final result - 1
Thread 0: Crunching some numbers! Final result - 7
Thread 2: Crunching some numbers! Final result - 8
Thread 1: Crunching some numbers! Final result - 2
Thread 2: Crunching some numbers! Final result - 4
Thread 0 waiting for others to reach barrier.
Thread 2: Crunching some numbers! Final result - 0
Thread 2 waiting for others to reach barrier.
Thread 1: Crunching some numbers! Final result - 7
Thread 1: Crunching some numbers! Final result - 6
Thread 1: Crunching some numbers! Final result - 9
Thread 1 waiting for others to reach barrier.
Thread 3: Crunching some numbers! Final result - 9
Thread 3: Crunching some numbers! Final result - 3
Thread 3: Crunching some numbers! Final result - 8
Thread 3: Crunching some numbers! Final result - 8
Thread 3: Crunching some numbers! Final result - 1
Thread 3: Crunching some numbers! Final result - 8
Thread 3: Crunching some numbers! Final result - 0
Thread 3: Crunching some numbers! Final result - 5
Thread 3: Crunching some numbers! Final result - 9
Thread 3: Crunching some numbers! Final result - 1
Thread 3 waiting for others to reach barrier.
Thread 4: Crunching some numbers! Final result - 2
Thread 4: Crunching some numbers! Final result - 2
Thread 4: Crunching some numbers! Final result - 5
Thread 4: Crunching some numbers! Final result - 5
Thread 4: Crunching some numbers! Final result - 3
Thread 4: Crunching some numbers! Final result - 7
Thread 4: Crunching some numbers! Final result - 4
Thread 4: Crunching some numbers! Final result - 8
Thread 4: Crunching some numbers! Final result - 4
Thread 4: Crunching some numbers! Final result - 3
Thread 4 waiting for others to reach barrier.
Thread 4: Computing sum of 5 workers, having 10 results each.
Adding 5 3 7 4 6 9 0 2 0 7
Adding 1 9 7 6 5 1 1 8 4 0
Adding 1 8 3 3 6 5 2 7 6 9
Adding 9 3 8 8 1 8 0 5 9 1
Adding 2 2 5 5 3 7 4 8 4 3
Thread 4: Final result = 230

Process finished with exit code 0

本文的例子可以参考​​https://github.com/ddean2009/learn-java-concurrency/tree/master/CyclicBarrier​​

版权声明:程序员胖胖胖虎阿 发表于 2022年10月9日 上午4:40。
转载请注明:java中CyclicBarrier的使用 | 胖虎的工具箱-编程导航

相关文章

暂无评论

暂无评论...